Charlie has 4 pairs of shoes, 12 shirts, 5 pairs of pants, and 3 watches. how many days could he go without wearing the same combination of these four items?

Charlie can go 720 days without wearing the same combination of these four items

Step-by-step explanation:

Each day Charlie is going to wear a pair of shoes, a shirt, a pair of pants and a watch.

So, for each pair of shoes, he can wear 12 shirts. For each shirt, he can wear 5 pair of pants. And for each pair of pants, he can wear a watch.

So, there are 5*3 = 15 possible combinations of watches and pants. For each one of these combinations, it can be worn with 12 shirts. So now there are 12*15 = 180 total combinations. Each one of these combinations can be worn with 4 pairs of shoes. So in all there are 720 total combinations, which means that Charlie can go 720 days without wearing the same combination of these four items.

all it means is function 3