)consider the initial value problem y′−5y=15t+3et, y(0)=y0 y′−5y=15t+3et, y(0)=y0 (a) solve the initial value problem. (enter y0 for y0y0). y(t)y(t)= equation editorequation editor (b) determine the value of y0y0 that separates solutions that grow positively as t→[infinity]t→[infinity] from those that grow negatively.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

copyright potato 2019.

c. 6tan80

step-by-step explanation: