What is the equation of a line parallel to y=-3x+5 that passes through point (6,8)

5y = 6x + 4

Step-by-step explanation:

from the given equation we have to calculate y-intercept and the slope.

y= -3x+5

when x=1

y=-3(1)+5

y=-3+5 = 2

.: slope = (y₂-y₁)/(x₂-x₁)

slope= (8-2)/(6-1)

slope= m= 6/5

now the intercept

y = mx+b

8 = (6/5)(6) +b

8=36/5 + b

b = 8 - 36/5

b = (8×5 - 36)/5

b= (40-36)/5

b = 4/5

.: the slope-intercept formula

y=mx+b

y=(6/5)x + 4/5

y = (6x +4)/5

5y = 6x+4

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d