Sketch the polar curves r = 6 sin θ and r = 2+ 2 sin θ, then set up an integral that represents the area inside r = 6 sin θ and outside r = 2 + 2 sin θ. do not evaluate your integral.

Step-by-step explanation:

Given are two polar curves as

Let us find the point/s of intersection

Eliminate r to get

Thus we find that area outside II curve and inside first curve would be

where lower limit is 30 degrees and 150 degrees.

10cm

step-by-step explanation:

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it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.