For a language test with normally distriuted scores, the mean was 70 and the standard deviation was 10. approximately what percentage of test takers scored a 60 or above?

84.13%

Step-by-step explanation:

Given : The scores in a a language test with normally distributed.

Mean :

Standard deviation:

Let x be the random variable that represents the scores of students.

Formula for z-score:

For x= 60 , we have

The probability f test takers scored a 60 or above :-

Hence, the percentage of test takers scored a 60 or above = 84.13%

65°

step-by-step explanation:

the total measure of a triangle is 180 degrees. 62 + 53 is 115.

180 - 115 = 65

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following