Probabilities with possible states of nature: s1, s2, and s3. suppose that you are given a decision situation with three possible state of nature: s1, s2, and s3.the prior probabilities are p(s1) =.1, p(s2) = .6, and p(s3) = .3.with sample information i, p(i|s1) =.15, p(i|s2) = .2, and p(i|s3) = .1.compute p(s1|i)compute p(s2|i)compute p(s3|i)

1.

2.

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Step-by-step explanation:

Given information:

(1)

We need to find the value of P(s₁|I).

Therefore the value of P(s₁|I) is .

(2)

We need to find the value of P(s₂|I).

Therefore the value of P(s₂|I) is .

(3)

We need to find the value of P(s₃|I).

Therefore the value of P(s₃|I) is .

$97520

step-by-step explanation:

add 6% to the value she got from selling the house.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)