Consider the series ∑n=1[infinity]2nn! nn. evaluate the the following limit. if it is infinite, type "infinity" or "inf". if it does not exist, type "dne". limn→[infinity]∣∣∣an+1an∣∣∣=l l= what can you say about the series using the ratio test? answer "convergent", "divergent", or "inconclusive". determine whether the series is absolutely convergent, conditionally convergent, or divergent. answer "absolutely convergent", "conditionally convergent", or "divergent".

I guess the series is

We have

Recall that

In our limit, we have

which is greater than 1, which means the series is divergent by the ratio test.

On the chance that you meant to write

we have

which is less than 1, so this series is absolutely convergent.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: