Hugo averages 58 words per minute on a typing test with a standard deviation of 11 words per minute. suppose hugo's words per minute on a typing test are normally distributed. let x= the number of words per minute on a typing test. then, x∼n(58,11). suppose hugo types 74 words per minute in a typing test on wednesday. the z-score when x=74 is this z-score tells you that x=74 is standard deviations to the (right/left) of the mean,

The number of words that Hugo wrote in the test of Wednesday (74) is at a distance of 1.4545 standard deviations (11) to the right of his mean (58)

Step-by-step explanation:

A normal random variable with mean Mu = 58 and standard deviation sd = 11 is standardized with the transformation (z-score):

Z = (X - Mu) / sd = (X - 58) / 11

For a value of 74 for X, Z = (74 - 58) / 11 = 1.4545 > 0.

The z-score when X = 74 is 1.4545 > 0

This means that the number of words that Hugo wrote in the test of Wednesday (74) is at a distance of 1.4545 standard deviations (11) to the right of his average (58)

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step-by-step explanation:

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