Consider the tangent line to the curve y = 6 sin(x) at the point (π/6, 3). (a) find a unit vector that is parallel to the tangent line to the curve at the given point.

Step-by-step explanation:

We have given the equation y = 6 sin (x)

On differentiating both side

As it passes through the point

So

Now the unit vector is parallel to the tangent so m will be 5.196

This passes through the point

So unit vector will be

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: