Jillian’s school is selling tickets for a play. the tickets cost $10.50 for adults and $3.75 for students. the ticket sales for opening night totaled $2071.50. the equation 10.50 a plus 3.75 b equals 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. if 82 students attended, how may adult tickets were sold?

The number of the adult tickets is 168

Step-by-step explanation:

* Lets explain how to solve the problem

- The adults ticket costs $10.50

- The students ticket costs $3.75

- The total money of the opening night is $2071.50

- The equation of the total money earned in the opening night is:

 10.50 a + 3.75 b = 2071.50, where a is the number of the adult ticket

  and b is the number of the student ticket

- There were 82 students attended

* Lets solve the problem

∵ 10.50 a + 3.75 b = 2071.50

∵ The number of the students attended is 82

∵ b is the number of the students

∴ b = 82

- Substitute the value of b in the equation

∴ 10.50 a + 3.75(82) = 2071.50

∴ 10.50 a + 307.5 = 2071.50

- Subtract 307.5 from both sides

∴ 10.50 a = 1764

- Divide both sides by 10.50

∴ a = 168

∵ a is the number of the adult tickets

∴ The number of the adult tickets is 168

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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