A, b and c are the vertices of a triangle. a has coordinates (4, 6). b has coordinates (2, -2). c has coordinates (-2, -4). d is the midpoint of ab. e is the midpoint of ac. prove that de is parallel to bc.
you!

well, first off let's find the midpoints of AB and AC.

now... let's check the slopes of DE and BC, bearing in mind that if they're indeed parallel lines, their slopes must be exactly the same.

Check the picture below.

50=33x+22

step-by-step explanation:

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."