two plans for reaching a goal are given below.
plan a: save $450 over the next 8 weeks by working 9 hours per week at $7.20 per hour.
plan b: save $450 over the next 6 weeks by working 15 hours per week at $6.50 per hour.
which of the following is a true statement?
a.
only plan a will work for achieving the goal.
b.
only plan b will work for achieving the goal.
c.
both plans will work for achieving the goal.
d.
neither plan will work for achieving the goal

C

Step-by-step explanation:

Plan A:

8 weeks by 9 hours per week = 72 hours in 8 weeks

$7.20 per hour

So,

Plan B:

6 weeks by 15 hours = 90 hours

$6.50 per hour

So,

Since and both plans will work for achieving the goal.

The answer is c. Both plans will work for achieving the goal.

Step-by-step explanation:

 In the first case you must determine the amount of money you save per week in both plans, and then with that data calculate the amount of money saved in 6 or 8 weeks, depending on the case. For these calculations, you use simple rules of three, as will be shown below:

Plan A:

As previously mentioned, you will first calculate the amount of money saved in a week using a simple rule of three knowing that it works 9 hours per week: If in one hour you get $ 7.20, how much can you save in 9 hours?

money saved=$64.8 in 1 week

$ 64.8 is the money saved in a week.

So if that is the amount saved in 1 week, how much money will you save in 8 weeks?

money saved=$518.4 in 8 weeks

So, since $518.40 is bigger than $450, plan A will work.

Plan B:

Solving in the same way as in plan A, you can obtain:

If in one hour you get $ 6.50, how much can you save in 15 hours?

money saved=$97.5 in 1 week

$ 97.5 is the money saved in a week.

So if that is the amount saved in 1 week, how much money will you save in 6 weeks?

money saved=$585 in 6 weeks

Since $585.00 is bigger than $450, plan B will work, too.

Thus, both plans will work for achieving the goal.

the answer is; biodiversity resulting from few ancestors

adaptive radiation occurs when a population is subjected to a large natural environment with spatial ecological variations. the parts of the population in the different ecologies begin to adapt to their local environments. due to non-random mating across the large populations, this causes the different populations from the large population to speciate within their local environments. they, therefore, diverge to different species sharing a common ancestor.  

so, converting firstly the mixed fractions to improper fractions and then "adding".