Which shows the image of quadrilateral abcd after the transformation r0, 90°?

The answer is A. on edgen

Step-by-step explanation:

A. the first graph

The second picture shows the transformation.

Step-by-step explanation:

To find the image lets apply the rotation rule counterclockwise about the origin:

R0,90° = R90°(x,y) = (-y,x)

We switch the coordinates of the point and change the sign of the y-coordinate

The coordinates of our quadrilateral ABCD are:

A = (-1, 0), B = (0, -1), C = (-2, -3), and D = (-3 , -2)

Now solve the coordinates by applying rotation rule:

A=(-1,0)

A' = (-y,x) = (-0,-1)=(0,-1)

B=(0,-1)

B'= (-y,x) = (-(-1),0)=(1,0)

C = (-2, -3)

C' = (3,-2)

D=(-3,-2)

D'=(2,-3)

Now the coordinates after the rotation of 90 degree are:

A'=(0,-1) , B'=(1,0) , C'=(3,-2) , D'=(2,-3)

The second picture shows the transformation after 90 degree

4th option is correct xy=-10

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step-by-step explanation: