mean, median, mode, and range (a)
instructions: calculate the mean, median, mode, and range of each set of numbers. (4 points each exercise)
{218, 365, 461, 512, 595, 595, 690, 739, 836, 836, 836, 896, 896, 954, 954}
result
calculation
mean
median
mode
range
{198, 212, 262, 284, 313, 488, 602, 602, 606, 616, 616, 678, 754, 937, 997}
result
calculation
mean
median
mode
range
{199, 504, 584, 677, 690, 709, 740, 740, 805, 836, 839, 839, 873, 987, 994}
result
calculation
mean
median
mode
range
{136, 238, 320, 403, 434, 553, 555, 571, 571, 581, 723, 824, 857, 948, 971}
result
calculation
mean
median
mode
range
{208, 226, 323, 433, 433, 489, 574, 594, 599, 803, 803, 803, 875, 951, 969}
result
calculation
mean
median
mode
range

1. {198, 212, 262, 284, 313, 488, 602, 602, 606, 616, 616, 678, 754, 937, 997}

Mean of given numbers is:

                = 692.2      

For finding Median, firstly we arrange data in ascending or descending order:   218, 365, 461, 512, 595, 595, 690, 739, 836, 836, 836, 896, 896, 954, 954

Here number of terms is 15 which is odd.

So, Median =  { (n + 1) ÷ 2 }th term

                  =  { (15 + 1) ÷ 2 }th term

                  = term

                  = 739

For finding mode, We see the observation that has maximum number of frequency.

Here 836 is repeated 3 times and its frequency is maximum.

So, Mode = 836

Range = Highest value - Lowest value

           = 954 - 218

           = 736

2. {198, 212, 262, 284, 313, 488, 602, 602, 606, 616, 616, 678, 754, 937, 997}

Mean of given numbers is:

                = 544.333      

For finding Median, firstly we arrange data in ascending or descending order:   198, 212, 262, 284, 313, 488, 602, 602, 606, 616, 616, 678, 754, 937, 997

Here number of terms is 15 which is odd.

So, Median =  { (n + 1) ÷ 2 }th term

                  =  { (15 + 1) ÷ 2 }th term

                  = term

                  = 602

For finding mode, We see the observation that has maximum number of frequency.

Here 616 is repeated 2 times and its frequency is maximum.

So, Mode = 616

Range = Highest value - Lowest value

           = 997 - 198

           = 799

3. {199, 504, 584, 677, 690, 709, 740, 740, 805, 836, 839, 839, 873, 987, 994}

Mean of given numbers is:

                = 734.4      

For finding Median, firstly we arrange data in ascending or descending order:   199, 504, 584, 677, 690, 709, 740, 740, 805, 836, 839, 839, 873, 987, 994

Here number of terms is 15 which is odd.

So, Median =  { (n + 1) ÷ 2 }th term

                  =  { (15 + 1) ÷ 2 }th term

                  = term

                  = 740

For finding mode, We see the observation that has maximum number of frequency.

Here 839 is repeated 2 times and its frequency is maximum.

So, Mode = 839

Range = Highest value - Lowest value

           = 994 - 199

           = 795

4. {136, 238, 320, 403, 434, 553, 555, 571, 571, 581, 723, 824, 857, 948, 971}

Mean of given numbers is:

                = 579      

For finding Median, firstly we arrange data in ascending or descending order:   136, 238, 320, 403, 434, 553, 555, 571, 571, 581, 723, 824, 857, 948, 971

Here number of terms is 15 which is odd.

So, Median =  { (n + 1) ÷ 2 }th term

                  =  { (15 + 1) ÷ 2 }th term

                  = term

                  = 571

For finding mode, We see the observation that has maximum number of frequency.

Here 571 is repeated 2 times and its frequency is maximum.

So, Mode = 571

Range = Highest value - Lowest value

           = 971 - 136

           = 835                

4. {136, 238, 320, 403, 434, 553, 555, 571, 571, 581, 723, 824, 857, 948, 971}

Mean of given numbers is:

                = 605.5333    

For finding Median, firstly we arrange data in ascending or descending order:   208, 226, 323, 433, 433, 489, 574, 594, 599, 803, 803, 803, 875, 951, 969

Here number of terms is 15 which is odd.

So, Median =  { (n + 1) ÷ 2 }th term

                  =  { (15 + 1) ÷ 2 }th term

                  = term

                  = 594

For finding mode, We see the observation that has maximum number of frequency.

Here 803 is repeated 3 times and its frequency is maximum.

So, Mode = 803

Range = Highest value - Lowest value

           = 969 - 208

           = 761  

the clues that signal the reader should change tone are the punctuation marks, the grammatical signs. for example, the quotation marks at the beginning of something someone else said literally or the exclamation marks.

the tone of the first line of dialogue until "gettysburg" is a kind tone, a tone of advise. the narrator is trying to the other person in doing something he or she obviously is finding hard to do by giving a piece of advise and bringing up a memory of a successful similar case.

the clue that the reader understand how to read the word "bang" is the exclamation mark. it gives the word a surprise tone, a strong accent.

the best tone for reading the word "bang" is an exciting tone, a surprise one, even a loud one.

the words that should be read with a formal tone are the ones that give factual information. the sentence: mister lincoln couldn't think of anything to say at the gettysburg" gives information about an event and it needs to be read formally, also, when the narrator wants to transmit calmness, a formal and slow tone is needed, because people also transmit messages with the vibrations of our voices and tones.

we'll this would mean that the dunk tank and the bounce house are the same for 20 hours because the 2 represents that the two activities, and the 20 represents the amount of hours they both are. so with this said, it means that the answer is c. the costs for a dunk tank and bounce house are the same for 20 hours.

c.the costs for a dunk tank and bounce house are the same for 20 hours.

hope this .