Which number line best shows the position of square root of 7? number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. a dot is made at 1.7 and labeled as square root of 7. number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. a dot is made at 2.6 and labeled as square root of 7. number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. a dot is made at 3.5 and labeled as square root of 7. number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. a dot is made at 4.5 and labeled as square root of 7.

Number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. A dot is made at 2.6 and labeled as square root of 7

Step-by-step explanation:

* Lets explain how to solve this problem

- We want to know the position of √7 on the number line, then:

1- Square the √7

# (√7)² = 7

2- Search 7 is between which two square numbers

# 7 is between 4 and 9 which are square numbers

3- ⇒ 4 < 7 < 9 ⇒ take √ for all

# 2 < √7 < 3

∴ The value of √7 is between 2 and 3

* Lets look to the answer to find the correct answer

∵ The first answer is:

   A dot is made at 1.7 and labeled as square root of 7

∵ 1.7 is not between 2 and 3

∴ The first answer is not true

∵ The second answer is:

   A dot is made at 2.6 and labeled as square root of 7

∵ 2.6 is between 2 and 3

∴ The second answer is true

∴ Number line with numbers negative 4, negative 3, negative 2,

  negative 1, 0, 1, 2, 3, 4 labeled. A dot is made at 2.6 and labeled

  as square root of 7

your answer is the last one

step-by-step explanation:

divide the length of a'c' by the length of ac to get a scale factor of two

& then reflect vertically (over the y-axis)

so your answer is dilation by a scale factor of 2 followed by reflection over the y-axis

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8