What is the slope of any line parallel to the line 8x- 10y = 12 ?

The slope of any line parallel to the given line is 0.8

Step-by-step explanation:

we have the line

8x-10y=42

Isolate the variable y

Adds 10y both sides

8x-10y+10y=42+10y

8x=42+10y

Subtract 42 both sides

8x-42=10y

Divide by 10 both sides

y=0.8x-4.2

The slope m is equal to

m=0.8

Remember that

If two lines are parallel, then their slopes are the same

therefore

The slope of any line parallel to the given line is 0.8

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step-by-step explanation:

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step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2