What is the value of (20-6)^2+6•2-(3+2)^2 ?
1. 10
2. 3
3. -1
4. -5

(14)^2+12-(5)^2

196+12-25

208-25

183 is the answer

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

ion

step-by-step explanation:

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