Aball is thrown vertically upward from the ground with an initial velocity of 60 ft/sec. how high will the ball go?

The ball will go to maximum height of 56.25 meters.

Step-by-step explanation:

It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec

Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :

h = 0

..............(1)

We need to find the maximum height reached by the ball. For maximum height,

t = 1.875 seconds

Put the values of t in equation (1). So,

h(t) = 56.25 meters

So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.

two data sets with the same median will not have the same varaibility

step-by-step explanation:

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7