In the formula a(t) = a0ekt, a(t) is the amount of radioactive material remaining from an initial amount a0 at a given time t and k is a negative constant determined by the nature of the material. a certain radioactive isotope decays at a rate of 0.1% annually. determine the half-life of this isotope, to the nearest year.

 693 years

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

k = rate constant

t = time taken for decomposition = 1

= Initial amount of the reactant

= amount of the reactant left =

for half life :

Putting in the values , we get

Thus half life of this isotope, to the nearest year is 693.

answer: the value of x is 7cm

step-by-step explanation: