Acar is moving with speed 40 m/s and acceleration 4 m/s2 at a given instant. using a second-degree taylor polynomial, estimate how far the car moves in the next second.

the estimate distance moved by the car will be equal to 42 m

Step-by-step explanation:

Using second degree polynomial

given,

y'₀ = 40 m/s                      y''₀ = 4 m/s²

at t = 0                              y₀ = 0

at t =1

y(1) = 40 ×1 + 2× 1²

y(1) = 42 m

hence, the estimate distance moved by the car will be equal to 42 m

answer: b

step-by-step explanation:

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6