![\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\implies cos(\theta)=\sqrt{1-sin^2(\theta)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(x)=cos(x)\implies sin(x)=\sqrt{1-sin^2(x)} \\[1.5em] [sin(x)]^2=\left[\sqrt{1-sin^2(x)}\right]^2\implies sin^2(x) = 1-sin^2(x)\implies 2sin^2(x)=1](/tpl/images/0186/3313/4bc3a.png)
Find all solutions of
sin(x) = cos(x)
in the interval [-π, π)...
Mathematics, 22.08.2019 00:30 daisa02
Find all solutions of
sin(x) = cos(x)
in the interval [-π, π)
Answers: 3
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