Ablimp is 1500 meters high in the air and measures the angles of depression to two stadiums to the west of the blimp. if those measurements are 72.9° and 34.1°, how far apart are the two stadiums to the nearest meter?

The distance between both stadiums is:

2215.49 m - 461.46 m =1754.03 m ....

Step-by-step explanation:

Look at the attached picture:

Lets say that the stadium on the left is stadium 1 and stadium 2 is on the right.

Using the angle property of alternate angles the angle above stadium 1 is 72.9°  and the angle above the stadium 2 is 34.1°

By using trigonometric function of tangent we solve it as:

We know that tanθ = opposite / adjacent

Therefore,

tan  72.9°=1500/ adjacent

Now

adjacent = 1500/tan 72.9°

adjacent = 461.46 m

Solve for next angle:

Tan 34.1°=1500/ adjacent

adjacent = 1500/tan 34.1°

adjacent = 2215.49 m

Therefore the distance between both stadiums is:

2215.49 m - 461.46 m =1754.03 m ....

its d. the first coordintaes are 10,32

step-by-step explanation:

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1