What’s the answer to this algebra question

x=9, x=7

Aka x= 9,7

Step-by-step explanation:

Oh goodie, factoring.

I used to be very good at this. My memory is a LITTLE rusty but let's see if we can bust out some penzoil and fix my aching joints (yes I just stole the quote from that terrible show, sue me), shall we?

1. x^2 - 11x + 68 = 5x +5

2. Chuck all the x variables to the left: x^2 - 16x + 68 = 5

3. Get rid of that pesky loser, 5, by subtracting from both sides of the equation (Note that it's important to remember LIKE TERMS, don't try subtracting 5 from 16x, you'll hurt yourself): x^2 - 16x + 68 - 5 = 5 - 5

New equation: x^2 - 16x + 63 = zilch (0)

4. Use AC method to factor: x2+bx+c. AC method definition: a pair of numbers whose product is c and whose sum is b: (x-9)(x-7)=0

5. Solve for x.

Booyah.