Solve for x: 3|2x - 2| + 6 = 18.
a) x = 3, x = -3
b) x = 3, x = -1
c) x = 1, x = -1
d) x =-3, x = 1

b) x = 3, x = -1

Step-by-step explanation:

3|2x - 2| + 6 = 18.

divid by 3 :

|2x - 2| + 2 = 6

add -2 :  |2x - 2|  = 4

2x-2=4 or 2x-2=-4

2x=6 or 2x=-2

x=3 or x=-1

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: