Suppose mr. garcia is making badges using 3/8 yards os ribbon for each badge. he starts with the same amount of ribbon, 3/4 yard. how many badges can he make? write a division equation that supports your answer.

He can make 2 badges

Step-by-step explanation:

* Lets explain how to solve the problem

- Mr.Garcia is making badges

- Each badge has 3/8 yards of ribbon

- He starts with 3/4 yard of ribbon

- We need to find how many badges he can make

∵ The length of each badge is 3/8 yard of ribbon

∵ The total length of the ribbon is 3/4 yard

- To find the number of the badges is the quotient of the division

  of the total length of the ribbon by the length of each badge

∵ The number of badges = the length of the ribbon ÷ the length

   of the badge

∴ The number of badges = ÷

- To solve the division of two fraction we change the division

  sign by the multiplication sign and reciprocal the fraction after

  the division sign

∴ The number of the badges = ×

∴ The number of the badges =

* He can make 2 badges

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.