Given the two sets, which statement is true?
а = {1, 2}
в = {1, 2, 3, 4}
b c a
3 c a
4 c a
a c b
none of the above

A⊆B

Step-by-step explanation:

C⊆D if the set C contains only elements from set D.

Let's look at the first choice:

B⊆A is not true because 3 and 4 are not in A.

Second choice:

3⊆A is not true because 3 is not a set; it is an element.

Also, 3 is not even in {1,2}.

Third choice:

See explanation for choice 2.

Fourth choice:

A⊆B is true because all the elements in A are contained in B.

That is the elements 1 and 2 are contained in the set {1,2,3,4} which is B.

step-by-step explanation:

jbjuiuhuhuuy

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb