Abin contains 78 light bulbs of which four are defective. if five are randomly selected from the bin without replacement, find the probability that all five are not defective.

0.7630

Step-by-step explanation:

Probaility of defective = 4/78

Probability of NOT defective = 1 - 4/78 = 74/78

Note: probability of NOT A = 1 - probability of A

Since without replacement, we need to consider that with each turn, 1 goes down from total and we multiply all the 5 outcomes, hence:

Probability 5 not defective =

THis is the answer, 0.7630

christopher is 272,195 year old

step-by-step explanation:

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: