Mathematics, 13.08.2019 05:20 esanchez2002fcb

Astudent was conducting a study to determine how many loose navel oranges that could be packed in different box sizes at the local farmer’s market.
using the collected data above, what would be a reasonable rough estimate of the ratio of how many cubic inches per orange?
a. 32.5 oranges per cubic inch
b. 32.5 cubic inches per orange
c. 0.03 oranges per cubic inch
d. 0.03 cubic inches per orange

Astudent was conducting a study to determine how many loose navel oranges that could be packed in di

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Answer from: misswonderless

B. 32.5 cubic inches per orange

Step-by-step explanation:

The question asks for "cubic inches per orange." Only two answer choices have those units. One of them is 32.5; the other is 0.03.

A cube that has a volume of 0.03 cubic inches has a side length of about 0.3 inches. Oranges aren't usually that small.

On the other hand, a cube with a volume of 32.5 cubic inches has a side length of about 3.2 inches. This is roughly the diameter of a typical orange, so is the best choice.

Roughly, the ratio of cubic inches to oranges is 32.5 cubic inches per orange.

_____

You can also plot the points on a graph and draw a line of best fit. It has a slope of about 32.5 cubic inches per orange.

_____

Comment on multiple choice problems

Often, a reasonable choice can be made based on the general nature of the relationships described in the problem. It is usually possible to eliminate several obviously wrong answers, sometimes leaving only the right one.

Astudent was conducting a study to determine how many loose navel oranges that could be packed in di

Answer from: natetheman7740

B. 32.5 cubic inches per orange

Step-by-step explanation:

A student was conducting a study to determine how many loose Navel oranges that could be packed in different box sizes at the local farmer’s market. Using the collected data given, the estimate of the ratio of how many cubic inches per orange are 32.5 cubic inches per orange.

Answer from: Quest

it will be a cylinder. with a diameter of 8 and 4 single pieces high

step-by-step explanation:

Answer from: Quest

the length of o'p' is $1.5\times op$ .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

$k=\frac{o'p'}{op}$

the scale factor is 1.5.

$1.5=\frac{o'p'}{op}$

multiply both sides by op.

$1.5\times op=o'p'$

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is $1.5\times op$ .

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