Find the recurrence relation satisfied by rn, where rn is the number of regions that a plane is divided into by n lines, if no two of the lines are parallel and no three of the lines go through the same point. b) find rn using iteration.

a) The recursion formula is .

b) .

Step-by-step explanation:

a) Let us explore the recurrence. A plane with only one line is divided in two regions, so . If we add another line under the restrictions of the problem, .

Notice that each line intersects the other n-1 lines, because there are no parallel lines. Assume we have n-1 lines and regions in the plane. If we add a new one we will have the previous plus n new regions. Because, for each line crossed by the new one there are a new region. Therefore,

.

b) The method here is to develop the recurrence and find some pattern. Hence, using the formula for , and we obtain

Notice that for each step back in the recurrence we add a new term in th sum. If we repeat the procedure n-1 times we will have

Using that :

Here the smart step is to split the first 2 in 1+1, in order to obtain the sum of the first n natural numbers, and the expression for this last sum it is well known. Therefore,

0

step-by-step explanation:

you can not divide by 0 so 4 ÷ 0 would be 0

0 × 9999 =0

mark brainliest   : )