Asimple random sample of 60 adults is obtained from a normally distributed population, and each person's red blood cell count (in cells per microliter) is measured. the sample mean is 5.25 and the sample standard deviation is 0.55. use a 0.05 significance level and the given calculator display to test the claim that the sample is from a population with a mean less than 5.4 comma which is a value often used for the upper limit of the range of normal values. what do the results suggest about the sample group?

Step-by-step explanation:

sample size = n = 60

Sample mean = x bar = 5.25

Sample sd = s = 0.55

Std error of sample = s/sqrt n = 0.071

(One tailed test)

Mean difference = 5.25-5.4 = -0.15

Test statistic t = Mean diff/Se = -2.11

df=59

(since population std dev is not known t test is used)

p value =0.01955

Since p <alpha =0.05 we reject null hypothesis.

The results suggest about the sample group that the sample is from a population with a mean less than 5.4

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)