The following list of rows of odd numbers continues in the same pattern: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19. each row starts where the previous left off, and has one more term than the previous row. there is one row in which the sum of the units digits of the numbers in that row equals 50. how many terms are in that row?

10 terms

Step-by-step explanation:

Given : A list of rows of odd numbers continues in the same pattern: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19 such that each row starts where the previous left off, and has one more term than the previous row.

To find : Number of terms in the row  in which the sum of the units digits of the numbers equal to 50.

List of rows of odd numbers :

First Row: 1

Second Row: 1  3

Third Row: 1   3  5

Fourth Row : 1  3  5  7

and so on.

Now if we write 1  3   5  ...  19, sum of unit digits = 1+3+5+7+9+1+3+5+7+9 = 50

Therefore, there are 10 terms in this row .

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