Auniversity surveyed recent graduates of the english department about their starting salaries. four hundred graduates returned the survey. the average salary was $25,000. assume for purposes of this problem that the population standard deviation is known, and it is $2,500. what is the 95% confidence interval for the mean salary of all graduates from the english department?

  (24755, 25245)

Step-by-step explanation:

Given : Sample size : n= 400

Sample mean :

Standard deviation :

Significance level :

Critical value :

The confidence interval for population mean is given by :-

Hence, the 95% confidence interval for the mean salary of all graduates from the English department is (24755, 25245)

the answer is b. 60. each interior angle in 120, so the exterior angle must be 60 in order to add up to 180

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116