The curve for which f'(x) = ax, where a is a constant, is such that the tangent at (1,2) passes through the origin. find the gradient of this tangent and hence determine:
a) the value of a
b) the equation of the curve

answer: the first graph

step-by-step explanation:

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

(-5,-28)

i graphed to on desmos.

96 39 cause 135 -96=39 im smart (i used a calculater)