Fazla has 30 coins, consisting of quarters and
nickels. if the total value of these coins is $5.50,
how many more nickels than quarters does he have?
have?

10

Step-by-step explanation:

20 quarters: $5 and

10 nickels: 50 cents

20-10=10

20 quarters ($5) and 10 nickels ($0.50)

Step-by-step explanation:

Q+ N = 30

Q = 30-N

0.5N + 0.25(30-N) = 5.50

0.5N + 7.50-0.25N = 5.50

-0.20N = -2

N=10            Q=30-N   Q=30-10       Q=20

10*0.5 = 0.50

20*0.25 = 5

5 + 0.5 =  $5.50

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?