The intelligence quotient (iq) test scores for adults are normally distributed with a population mean of 100 and a population standard deviation of 15. what is the probability we could select a sample of 50 adults and find the mean of this sample is between 95 and 105?

0.9817

Step-by-step explanation:

Given : The Intelligence Quotient (IQ) test scores for adults are normally distributed with

Mean :

Standard deviation :

Sample size : = 50

Let x be the random variable that represents the IQ test scores for adults.

Z-score :

For x =95

For x =105

By using standard normal distribution table , the probability the mean of the sample is between 95 and 105 :-

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

answer: r there any options?

step-by-step explanation: