3tan 3 ѳ - sqrt 3 = 0 given that 0< = ѳ < = 360

see explanation

Step-by-step explanation:

Given

3tan3Θ - = 0 ( add to both sides )

3tan3Θ = ( divide both sides by 3 )

tan3Θ = , then

For 3 Θ we require to go round the unit circle 3 times, that is

0 ≤ 3Θ ≤ 1080

Since tan3Θ > 0 then Θ in first/ third quadrants

3Θ = 30, 210, 390, 570, 750, 930 ( divide by 3 )

Θ = 10, 70, 130, 190, 250, 310 for 0 ≤ Θ ≤ 360

the answer is d. (1.2, -4.7) on edgn

hope this !