4. a homeowner is deciding on the size of tiles to use to fully tile a rectangular wall in her bathroom that is
80 inches by 40 inches. the tiles are squares and come in three side lengths: 8 inches, 4 inches, and
2 inches. state if you agree with each statement about the tiles. explain your reasoning
a. regardless of the size she chooses, she will need the same number of tiles
b. regardless of the size she chooses, the area of the wall that is being tiled is the same
c. she will need two 2-inch tiles to cover the same area as one 4-inch tile.
d. she will need four 4-inch tiles to cover the same area as one 8-inch tile.
e. if she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles,
(from unit 1, lesson 2)

b. Regardless of the size she chooses, the area of the wall that is being tiled is the same

Reason: The area of the wall must be the same as the area of the tiles irrespective of the measure of tiles.

c. She will need four 4-inch tiles to cover the same area as one 8-inch tile.

Reason: Area of one 8-inches = 4 *area of one 4-inch tiles

64 = 4*16

64 = 64

Step-by-step explanation:

Let's find the area of the rectangular wall of the bathroom.

Area of the rectangular wall = length x width

= 80 x 40

= 320 square inches.

Now let's find the area of each tiles.

All the tiles are in square shapes.

Area of the tile which is 8 inches in length = 8 x 8 = 64 square inches

Area of the tile which is 4 inches in length = 4 x 4 =  16 square inches

Area of the tile which is 2 inches in length = 2 x 2 = 4 square inches

Let's find the number of tiles needed to tile the rectangular wall.

The number 8 inches tiles needed = tiles

The number 4 inches tiles needed = tiles

The number 2 inches tiles needed = tiles

Now let's find the correct statements.

b. Regardless of the size she chooses, the area of the wall that is being tiled is the same

Reason: The area of the wall must be the same as the area of the tiles irrespective of the measure of tiles.

c. She will need four 4-inch tiles to cover the same area as one 8-inch tile.

Reason: Area of one 8-inches = 4 *area of one 4-inch tiles

64 = 4*16

64 = 64

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

b

step-by-step explanation: