Find (f-g)(x) for the following functions. f(x) = 12x + 20 g(x) = –11x2 + 10x + 33
11x2 + 2x – 13
–11x2 – 2x + 13
23x2 – 10x – 13
–11x2 – 2x – 13

11x2 + 2x-13

Step-by-step explanation:

We must build the new function f-g, which turns to be a sum between polynomials.

f(x)-g(x)= 12x+20 + 11x2- 10x-33

f(x)-g(x)= 12x+20 + 11x2- 10x-33

f(x)-g(x)= 11x2 + 2x-13

a = 11 : 4

b = 38

c = 1 for every 6

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.