Amarketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. the ceo of the chain hypothesized that the average customer spends at least $13.50 on lunch. a survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be ¯=$14.50 . based on previous surveys, the restaurant informs the marketing manager that the standard deviation is =$3.50 . lunch bills are normally distributed. to address the ceo’s conjecture, the marketing manager carried out a hypothesis test of : =13.50 vs. : > 13.50 . using the test statistic ¯−13.50)/√ , the ‑value for the hypothesis test equals:

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

answer: the correct answer is -32

step-by-step explanation:

answer: 323 is how many she has ☃☃⛄❄

step-by-step explanation: