Explain how system 1 becomes equivalent to system 2.
system 1:
ax + by = c
lx + my = n
system 2:
ax + by = c
(a − l)x + (b − m)y = c − n

In the procedure

Step-by-step explanation:

we have

System 1

Ax+By=C > equation A

Lx+My=N > equation B

step 1

Multiply equation B by -1 both sides

(-1)*(Lx+My=)N*(-1)

-Lx-My=-N > equation C

step 2

Adds equation A and equation C

Ax+By=C

-Lx-My=-N

Ax-Lx+By-My=C-N

(A-L)x+(B-M)y=C-N > equation D

step 3

An equivalent system (System 2) is formed with

Ax+By=C > equation A

(A-L)x+(B-M)y=C-N > equation D