Find the bases for col a and nul a, and then state the dimension of these subspaces for the matrix a and an echelon form of a below 1 2 -2 1 3 1 2 2 3 5 10 1-28 8 0 0 1-3 0 -24 1 7-6 0 0 0 0 0 a basis for col a is given by (use a comma to separate vectors as needed.) the dimension of col a is a basis for nul a is given by (use a comma to separate vectors as needed.) the dimension of nul a is

236 cm 16 time 12 = 192

6 times 7 = 42

192+42

the equation of the parabola is y2=12x

explanation:

the vertex is midway between the focus ad the directrix

so, the vertex is (0,0)

let p=(x,y) be a point on the parabola.

the distance of p from the directrix is equal to the distance from the focus.

x+3=√(x−3)2+(y−0)2

(x+3)2=(x−3)2+y2

x2+6x+9=x2−6x+9+y2

y2=12x

graph{y^2=12x [-10, 10, -5, 5]}

the answer to your question is 10-5x+3r