Suppose that we have a white urn containing five white balls and one red ball and we have a red urn containing one white ball and
four red balls. an experiment consists of selecting at random a ball from the white urn and then (without replacing the first ball) selecting at random a ball from the urn having the color of the first ball. find the probability that the second ball is red. what is the probability that the second ball is red is?

0.36

Step-by-step explanation:

here there are two situation

1. from white urn the first ball chosen is white

P(probability of first ball white)= 4/5

now P( second ball red) = 1/5

total probability of second ball being red = (4/5)*(1/4)= 4/20

2. from the white urn first ball chosen is red

P(first ball red )= 1/5

now, P(second ball red from red urn)= 4/5

total probability of second ball being red = (1/5*4/5)= 4/25

now considering both the situation the total probability that the second ball is red

= 4/20 + 4/25 = 9/25= 0.36

75%

step-by-step explanation:

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this