T(x) = ax^5 + 2 where is a real number. if the points (-2,66) and (2,-62) are on the graph of the function classify as one of the following. a. a> 1 b. a< -1 c. 0> a> -1 d. 0

b. the decimal could be two-tenths.

step-by-step explanation:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation