Let a = {2r+1 | te n} and b = {2ss € z}. (a) is a cb? if it is, give a careful proof. if it is not, give a counterexample and explain. setement is the issure a: elf iren} {bz {2, is e23 let res a-23+1 berls. -5 (b) is b c a? if it is, give a careful proof. if it is not, give a counterexample and explain. statenet istak - 5

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

y > 1/3x

y < = -x + 4

hope this : )

false

step-by-step explanation: