An artist has 600 inches of framing material to form a rectangular frame. the dimensions of the wall on which it will hang limit the frame's width to no more than 200 inches. the artist wants the length to be at least 2 times longer than the width. write a system to represent this situation.

Step-by-step explanation:

We assume the problem wording means the length is to be at least 2 times as long as the width. (Longer than usually refers to a difference, not a scale factor.)

If we let "W" and "L" represent the width and length, respectively, then we can translate the problem statement to ...

  2(L + W) ≤ 600 . . . . . . the perimeter is twice the sum of length and width

  W ≤ 200 . . . . . . . . . . . . the width is at most 200 inches

  L ≥ 2W . . . . . . . . . . . . . the length is at least twice the width

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5

probably .5

i can on others if necessary.