Me with this☺️
1. what is the perimeter of a triangle with sides that measure 3 3/6 cm, 9 1/8 cm and 6 cm, respectively?

The perimeter of the triangle is P=a+b+c

where a, b and c are sides of the triangle.

a=3 3/6 cm

b=9 1/8 cm

c=6 cm

Now a=21/6 cm, b=73/8 cm, c=6 cm

We have to take LCM in order to make the denominator same.

Now, the LCM is 48

21*8/6*8 + 73*6/8*6 + 6*48/48

168/48 + 438/48 + 288/48

= 894/48 cm

try soting them out first

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.