In order to estimate the height of a building, two students stand at a certain distance from the building at street level. from this point, they find the angle of elevation from the street to the top of the building to be 39°. they then move 300 feet closer to the building and find the angle of elevation to be 50°. assuming that the street is level, estimate the height of the building to the nearest foot.

758 ft

Step-by-step explanation:

Note: Refer to the figure

Now from the figure:

In Δ AOD

tan 39° = H/(300 + x)      .................(1)

and in Δ BOD

tan50° = H/x   .................(2)

on dividing 1 by 2 we get

0.6794 = x/(300 + x)

or

203.84 + 0.6794x = x

or

0.3206x = 203.84

or

x = 635.80 ft

now using the equation (2)

we get

tan 50° = H/x

or

H = xtan50°

on substituting the value of x, we get

H = 635.80 × tan 50

or

H = 757.72 ft ≈ 758 ft

answer:

step-by-step explanation:

i need a picture

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