A
50%
antifreeze solution is to be mixed with a
90%
antifreeze solution to get
200
liters of a
80%
solution. how many liters of the
50%
solution and how many liters of the
90%
solution will be used

The number of liters of 50% antifreeze solution is 50 and the number of liters of 90% antifreeze solution is 150

Step-by-step explanation:

Let

x > number of liters of 50% antifreeze solution

y > number of liters of 90% antifreeze solution

we know that

50%=50/100=0.50

90%=90/100=0.90

80%=80/100=0.80

x+y=200

x=200-y > equation A

0.50x+0.90y=0.8(200) > equation B

substitute equation A in equation B and solve for y

0.50(200-y)+0.90y=160

100-0.50y+0.90y=160

0.40y=160-100

0.40y=60

y=150 liters

Find the value of x

x=200-y

x=200-150=50 liters

therefore

The number of liters of 50% antifreeze solution is 50

The number of liters of 90% antifreeze solution is 150

i dony know

step-by-step explanation:

answer: f = 32.2m

step-by-step explanation: that is the answer