For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. minitab was used to find that the value of the linear correlation coefficient is requals0.952. using alphaequals0.05, determine if there is a linear correlation between chest size and weight. what proportion of the variation in weight can be explained by the linear relationship between weight and chest size?

Step-by-step explanation:

Given that for a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears.

r = linear correlation coeff = 0.952

H_0: r =0\\

H_1 :r\neq 0

(Two tailed test)

r difference = 0.952

n=8

Std error = \sqrt{\frac{1-r^2}{n-2} } =0.12496

Test statistic t = 0.952/0.12496 = 7.618

Alpha = 0.05

df = 6

p value = 0.000267

This implies H0 is rejected.

There exists a linear relation between the variables and r cannot be 0

0.952^2 = 0.906=90.6% of variation in weight can be explained by the linear relationship between weight and chest size

answer: 25.4 units

step-by-step explanation: radius = 12.7 units

diameter = twice the radius

diameter = 12.7 x 2

= 25.4

the answer is stop cheating on things stoopid

step-by-step explanation:

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