Afootball player is running the length of a 100 yard long football field. for the first part of the field, he runs at a rate of 2 yards per second. he sprints the last part of the field at a rate of 4 yards per second. if the whole run takes 40 seconds, what is the fraction of the length of the field that the runner covers during the second sprint?

th part of the field is covered in the second sprint.

Step-by-step explanation:

A football player is running the length of a 100 yard long football field.

Let player sprints x yards with the speed = 2 yards per second.

So time taken to cover x yards player will take time = seconds

Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance =

= seconds

Now total time taken by the player can be represented by the equation

Now we can solve this equation for the value of x.

x + 100 = 40×4

x + 100 = 160

x = 160 - 100 = 60 yards

And length of the second part will be = 100 - 60 = 40 yards

Now the fraction of the field covered by the player in second sprint will be

=

= or 40%

Therefore, th part of the field was covered in second sprint.

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )